document.write( "Question 22654: Given two n x n matrices A and B where AB=BA how does one show that the
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document.write( "determinant of (A^2 + B^2) >=0? \n" );
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Algebra.Com's Answer #11250 by khwang(438)![]() ![]() ![]() You can put this solution on YOUR website! Given two n x n matrices A and B where AB=BA how does one show that the \n" ); document.write( "determinant of (A^2 + B^2) >=0? \r \n" ); document.write( "\n" ); document.write( " What level of linear algebra you are studying?\r \n" ); document.write( "\n" ); document.write( " It seems we have to use eigenvectors to prove it.\r \n" ); document.write( "\n" ); document.write( " AB=BA (commute) implies there is a basis of non-zero eigenvector say \n" ); document.write( " {vi | i=1,2,..n} in \n" ); document.write( " \n" ); document.write( " ci,di for each i.\r \n" ); document.write( "\n" ); document.write( " Since for each i, we have ( \n" ); document.write( " = \n" ); document.write( "\n" ); document.write( " Also, note that det( \n" ); document.write( " of the matrix \n" ); document.write( " Hence, det( \n" ); document.write( "\n" ); document.write( " Try to read carefully and understand the above proof.\r \n" ); document.write( "\n" ); document.write( " Good luck!\r \n" ); document.write( "\n" ); document.write( " Kenny\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |