document.write( "Question 153004: Show that the equation (x-a)(x-b)+(x-b)(x-c)+(x-a)(x-c)=0 has equal roots when a=b=c \n" ); document.write( "
Algebra.Com's Answer #112478 by jim_thompson5910(35256)\"\" \"About 
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\"%28x-a%29%28x-b%29%2B%28x-b%29%28x-c%29%2B%28x-a%29%28x-c%29=0\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-a%29%28x-a%29%2B%28x-a%29%28x-a%29%2B%28x-a%29%28x-a%29=0\" Plug in \"b=a\" and \"c=a\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-2ax%2Ba%5E2%2Bx%5E2-2ax%2Ba%5E2%2Bx%5E2-2ax%2Ba%5E2=0\" FOIL\r
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\n" ); document.write( "\n" ); document.write( "\"3x%5E2-6ax%2B3a%5E2=0\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"3%28x-a%29%5E2=0\" Factor the left side\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-a%29%5E2=0\" Divide both sides by 3.\r
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\n" ); document.write( "\n" ); document.write( "\"x-a=0\" Take the square root of both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x=a\" Add \"a\" to both sides.\r
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\n" ); document.write( "\n" ); document.write( "So the expression \"%28x-a%29%28x-b%29%2B%28x-b%29%28x-c%29%2B%28x-a%29%28x-c%29\" has a root of \"x=a\" (with a multiplicity of 2) if \"a=b=c\"
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