document.write( "Question 153020: A certin sum of money is invested at 10%. Twice that amount is invested at 8%. The total amount of intrest from both investments is $91. How much is invested at 8%. \n" ); document.write( "
Algebra.Com's Answer #112470 by nerdybill(7384)\"\" \"About 
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Let x = amount invested at 8%
\n" ); document.write( "then
\n" ); document.write( "x/2 = amount invested at 10%
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\n" ); document.write( "From the statement of the problem, we derive our equation of:
\n" ); document.write( ".10(x/2) + .08x = 91
\n" ); document.write( ".05x + .08x = 91
\n" ); document.write( ".13x = 91
\n" ); document.write( "x = 91/.13
\n" ); document.write( "x = $700 (amount invested at 8%)
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