document.write( "Question 153016: a triangular sail has an area of x squared +5x+6 squared meters and a height of x+3 meters. find the length of the sail's base. \n" ); document.write( "
Algebra.Com's Answer #112465 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
The problem expects that you know the formula for any triangle is:
\n" ); document.write( "area = (1/2)bh
\n" ); document.write( "where
\n" ); document.write( "b is the length of the base of the triangle
\n" ); document.write( "h is the height of the triangle
\n" ); document.write( ".
\n" ); document.write( "Your problem defines:
\n" ); document.write( "area = x^2 + 5x + 6 square meters
\n" ); document.write( "h = x+3 meters
\n" ); document.write( ".
\n" ); document.write( "All we need to do now, is plug in our given values and solve for 'b':
\n" ); document.write( "area = (1/2)bh
\n" ); document.write( "x^2 + 5x + 6 = (1/2)b(x+3)
\n" ); document.write( "Start, by multiplying both sides by 2:
\n" ); document.write( "2(x^2 + 5x + 6) = b(x+3)
\n" ); document.write( "Now, we divide both sides by (x+3):
\n" ); document.write( "[2(x^2 + 5x + 6)]/(x+3) = b
\n" ); document.write( ".
\n" ); document.write( "At this point, we can factor the numerator:
\n" ); document.write( "[2(x^2 + 5x + 6)]/(x+3) = b
\n" ); document.write( "[2(x+3)(x+2)]/(x+3) = b
\n" ); document.write( "Canceling like-terms we finally get:
\n" ); document.write( "2(x+2) = b (this is your answer)
\n" ); document.write( "or you could re-write it as:
\n" ); document.write( "2x+4 = b \r
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