document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=152983>Question 152983</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jon has three times as many dimes as he does quarters. He has as many nickels as he has dimes and quarters combined. The total numbers of money he has is 3.00. How many of each coin does he have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #112454 by </B><A HREF=/tutors/aboutme.mpl?userid=orca><B>orca(409)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=orca><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=112454\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the number of quarters, then the number of dimes is 3x, and the number of nickels is 3x + x = 4x<BR>\n" );
document.write( "The value of nickels: 5*4x=20x<BR>\n" );
document.write( "The value of dimes: 10*3x=30x<BR>\n" );
document.write( "The value of quarters: 25x.<BR>\n" );
document.write( "As the total value of money he has is 300 cents, we have<BR>\n" );
document.write( "20x + 30x + 25x = 300<BR>\n" );
document.write( "Solving for x, we obtain:<BR>\n" );
document.write( "75x = 300<BR>\n" );
document.write( "x = 4<BR>\n" );
document.write( "So he has<BR>\n" );
document.write( "4 quarters<BR>\n" );
document.write( "3x = 3*4 = 12 dimes<BR>\n" );
document.write( "4x = 4*4 = 16 nickels\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );