document.write( "Question 152982This question is from textbook Intermediate Algebra
\n" ); document.write( ": I need help! I am trying to figure this problem out. The problem is to solve by factoring: x^2-13x=-12
\n" ); document.write( "If someone can help, I need it! \n" ); document.write( "

Algebra.Com's Answer #112450 by orca(409) $\"\"$ $\"About$

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First write the equation in standard form:
\n" ); document.write( " $\"x%5E2-13x%2B12=0\"$
\n" ); document.write( "Note that 12 can be factored as 12= (-1)*(-12), and the sum of the two factors is 13, which is equal to the coefficient of the middle term of the equation.
\n" ); document.write( "Thus the left side of the equation can be factored as
\n" ); document.write( " $\"%28x-1%29%28x-12%29=0\"$
\n" ); document.write( "So x - 1 = 0 or x - 12 = 0
\n" ); document.write( "From x - 1 = 0 we have x = 1
\n" ); document.write( "From x - 12 = 0 we have x = 12
\n" ); document.write( "Thus the solutions to the equation are:
\n" ); document.write( "x = 1 or x = 12.
\n" ); document.write( " \n" ); document.write( "

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