document.write( "Question 152962: 4x+3≤-5 and 3x-2<7
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document.write( "I tried on the first and got x≤-2 and the second x<3 but the answer is said to be x≤-3, I don't know if I'm doing it wrong, or the answer is just wrong. \n" );
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Algebra.Com's Answer #112436 by edjones(8007) You can put this solution on YOUR website! 4x+3≤-5 and 3x-2<7 \n" ); document.write( ". \n" ); document.write( "4x+3≤-5 \n" ); document.write( "4x<=-8 \n" ); document.write( "x<=-2 \n" ); document.write( ". \n" ); document.write( "3x-2<7 \n" ); document.write( "3x<9 \n" ); document.write( "x<3 \n" ); document.write( "This 2nd answer is consistent with the 1st. It just doesn't add any information that we didn't know already from x<=-2 \n" ); document.write( "The answer on the number line extends from -2 to infinity. \n" ); document.write( "x[-2,infinity) \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " |