document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=152913>Question 152913</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0131139487/algebrahomeworkh>introductory mathematical analysis  , for business ,economics and the life and social science</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Hi iam having some problems with this question, i would appreciate it very much if you could solve it for me, thank you.\r<BR>\n" );
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document.write( "Equalizing cost.\r<BR>\n" );
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document.write( "  United products co. manufactures calculators and has plants in the cities  of Exton AND WHYTON .At the Exton plant, fixed  cost are $7000 per  month , and cost of producing each calculator is $7.50.At the Whyton plant ,fixed cost are $8800 per month ,and each calculator costs $6.00 to produce .Next month ,United products must produce 1500 calculators.How many must be made at each plant if the total cost at each plant is be the same  <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #112435 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=112435\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let E = the monthly cost at the Exton plant to produce x calculators.<BR>\n" );
document.write( "Let W = the monthly cost at the Whyton plant to produce (1500-x) calculators.<BR>\n" );
document.write( "As you can see, the number of calculators produced by the two plants together is (x+ (1500-x) = 1500).<BR>\n" );
document.write( "Let's write the equations for the monthly cost at each plant:<BR>\n" );
document.write( "E = $7000+($7.50)(x) This is the cost at the Exton plant.<BR>\n" );
document.write( "W = $8800+($6.00)(x) This is the cost at the Whyton plant.<BR>\n" );
document.write( "The problem asks \"how many calculators should be produced at each plant if the total cost is to be the same at each plant.<BR>\n" );
document.write( "So we set E = W and solve for x and then 1500-x.<BR>\n" );
document.write( "$7000+$7.50(x) = $8800+$6.00(1500-x) Simplify and solve for x.<BR>\n" );
document.write( "7000+7.5x = 8800+9000-6x<BR>\n" );
document.write( "7000+7.5x = 17800-6x Subtract 7000 from both sides.<BR>\n" );
document.write( "7.5x = 10800-6x  Add 6x to both sides.<BR>\n" );
document.write( "13.5x = 10800 Finally, divide both sides by 13.5<BR>\n" );
document.write( "x = 800 and (1500-x) = (1500-800) = 700<BR>\n" );
document.write( "So the Exton plant must produce <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28800%29 ALIGN=MIDDLE  ALT=\"highlight%28800%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > calculators and the Whyton plant must produce <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28700%29 ALIGN=MIDDLE  ALT=\"highlight%28700%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > calculators for a total of 1500 calculators for the total cost at each plant to be the same.<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "E = $7000+$7.50(800) = $7000+$6000 = $1300<BR>\n" );
document.write( "W = $8800 +$6.00(700) = $8800+$4200 = $1300<BR>\n" );
document.write( "The cost is the same at each plant! </SPAN>\n" );
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