document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=152932>Question 152932</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve each system by graphing.<BR>\n" );
document.write( "y=-1/2x-3<BR>\n" );
document.write( "y=-7/2x=3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #112433 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=112433\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y=-1/2x-3 (red line)<BR>\n" );
document.write( "y=-7/2x+3 (green line) I'll assume the second =sign should be a +<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+300%2C+200%2C+-3%2C+3%2C+-3%2C+3%2C+x%2F2+-3%2C+-7x%2F2+%2B3%29+ ALIGN=MIDDLE  ALT=\"+graph%28+300%2C+200%2C+-3%2C+3%2C+-3%2C+3%2C+x%2F2+-3%2C+-7x%2F2+%2B3%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > (graph 300x200 pixels, x from -3 to 3, y from -3 to 3, of TWO functions x/2 -3 and -7x/2 +3). <BR>\n" );
document.write( "answer (1.5,2.25) </SPAN>\n" );
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