document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=152930>Question 152930</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find a slope of a line perpendicular to each given line.<BR>\n" );
document.write( "0=3+x<BR>\n" );
document.write( "-3y=12x+9 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #112403 by </B><A HREF=/tutors/aboutme.mpl?userid=nabla><B>nabla(475)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nabla><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=112403\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perpendicular slopes to given lines involve taking some m value in:<BR>\n" );
document.write( "y=mx+b and taking its negative reciprocal.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "So,<BR>\n" );
document.write( "0=3+x  we have m=1. So -1 would be a perpendicular slope.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "-3y=12x+9<BR>\n" );
document.write( "y=-4x-3  we have m=-4. So 1/4 would be a perpendicular slope. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );