document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=152935>Question 152935</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 5m greater than the width.<BR>\n" );
document.write( "The perimeter is 150m. find the width and length. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #112395 by </B><A HREF=/tutors/aboutme.mpl?userid=orca><B>orca(409)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=orca><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=112395\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the width of the rectangle, then the length of it is x + 5.<BR>\n" );
document.write( "As the perimeter is 150, we can set up an equation using this fact:<BR>\n" );
document.write( "2x + 2(x + 5) = 150<BR>\n" );
document.write( "Solving for x, we obtain:<BR>\n" );
document.write( "2x + 2x + 10 = 150<BR>\n" );
document.write( "4x + 10 = 150<BR>\n" );
document.write( "4x = 140<BR>\n" );
document.write( "x = 35<BR>\n" );
document.write( "so the width and length are 35 and (35 + 5 =)40 meters.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );