document.write( "Question 152862: Consider polynomial \"g%28x%29+=+x%5En+%2B+4x%5E%28n-1%29\"; what is its maximum number of zeroes? @ The maximum number of zeroes = n, regardless of the value of n.
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Algebra.Com's Answer #112387 by Edwin McCravy(20060)\"\" \"About 
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Consider polynomial \"g%28x%29+=+x%5En+%2B+4x%5E%28n-1%29\"; what is its maximum number of zeroes? @ The maximum number of zeroes = n, regardless of the value of n.
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document.write( "We apply Descartes' rule of signs, which says:\r\n" );
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document.write( "If f(x) = a polynomial in descending order, then:\r\n" );
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document.write( "1. The maximum number of positive zeros of polynomial f(x),\r\n" );
document.write( "is the number of sign changes in f(x), going left to right.\r\n" );
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document.write( "2. The maximum number of negative zeros of polynomial f(x),\r\n" );
document.write( "is the number of sign changes in f(-x), going left to right.\r\n" );
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document.write( "\"g%28x%29+=+x%5En+%2B+4x%5E%28n-1%29\"\r\n" );
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document.write( "has only two terms, and NO sign changes. Therefore it has NO\r\n" );
document.write( "POSITIVE zeros.\r\n" );
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document.write( "Now let's test it for NEGATIVE zeros.\r\n" );
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document.write( "We form \"g%28-x%29\" by replacing \"x\" by \"-x\".\r\n" );
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document.write( "\"g%28-x%29+=+%28-x%29%5En+%2B+4%28-x%29%5E%28n-1%29\"  \r\n" );
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document.write( "Now since we do not know whether n is even or odd, we have to\r\n" );
document.write( "consider both cases:\r\n" );
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document.write( "If \"n\" is even, then \"n-1\" is odd, so \"%28-x%29%5En=x%5En\" and\r\n" );
document.write( "\"%28-x%29%5E%28n-1%29=-x%5E%28n-1%29\"\r\n" );
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document.write( "So in this case\r\n" );
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document.write( "\"g%28x%29=x%5En-x%5E%28n-1%29\"\r\n" );
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document.write( "That has 1 sign change, so g(x) would have a maximum of 1 negative zero.\r\n" );
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document.write( "If \"n\" is odd, then \"n-1\" is even, so \"%28-x%29%5En=-x%5En\" and\r\n" );
document.write( "\"%28-x%29%5E%28n-1%29=x%5E%28n-1%29\"\r\n" );
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document.write( "So in this case\r\n" );
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document.write( "\"g%28x%29=-x%5En%2Bx%5E%28n-1%29\"\r\n" );
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document.write( "That also has 1 sign change, so g(x) would have a maximum of 1 \r\n" );
document.write( "negative zero regardless of whether n is even or odd.\r\n" );
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document.write( "Now we know that it has no positive zeros, a maximium of\r\n" );
document.write( "1 negative zero.\r\n" );
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document.write( "However we must also check to see if 0, which is neither\r\n" );
document.write( "positive nor negative, is a zero.  So we find \"g%280%29\"\r\n" );
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document.write( "\"g%28x%29+=+x%5En+%2B+4x%5E%28n-1%29\" \r\n" );
document.write( "\"g%280%29+=+0%5En+%2B+4%280%29%5E%28n-1%29\"\r\n" );
document.write( "\"g%280%29+=+0\"\r\n" );
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document.write( "Therefore 0 is also a zero, regardless of n.\r\n" );
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document.write( "So the maximium number of zeros is 2. \r\n" );
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document.write( "Since 2 is not listed as a choice, then the only correct\r\n" );
document.write( "choice is d \"None of the above\".\r\n" );
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document.write( "Comment:\r\n" );
document.write( "It's easy to see the correct choice cannot be 0 or 1 \r\n" );
document.write( "because when \"n=2\"\r\n" );
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document.write( "\"g%28x%29=x%5E2%2B4x\"\r\n" );
document.write( "\"g%28x%29=x%28x%2B4%29\"\r\n" );
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document.write( "This has two zeros 0 and -4.\r\n" );
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document.write( "And we showed above that c cannot be the answer,\r\n" );
document.write( "for we were able to determine that the maximum number\r\n" );
document.write( "of zeros is 2. \r\n" );
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document.write( "Edwin

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