document.write( "Question 152908: The rate of motorcycle is 40 mph greater than the rate of a bicycle. The motorcycle travels 150 miles in the same amount of time as the bicycle travels 30 miles. Find the rate of the motocycle.\r
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document.write( "two people working together can do a job in 3 hrs. How long will it take the slower person to do the same job if one of them is 3 times as fast as the other?\r
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Algebra.Com's Answer #112366 by mangopeeler07(462) ![]() You can put this solution on YOUR website! The rate of motorcycle is 40 mph greater than the rate of a bicycle. The motorcycle travels 150 miles in the same amount of time as the bicycle travels 30 miles. Find the rate of the motocycle.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "m=rate of motorcycle \n" ); document.write( "b=rate of bike \n" ); document.write( "m=b+40\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "150/b+40=30/b-----------------------because miles over mph gives you the time, which is equal in this case.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Cross multiply \n" ); document.write( "150b=30b+1200\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Subtract 30b from both sides \n" ); document.write( "120b=1200\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Divide both sides by 120 \n" ); document.write( "b=10\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "m=b+40 \n" ); document.write( "m=10+40 \n" ); document.write( "m=50\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: \n" ); document.write( "Bike=10mph \n" ); document.write( "Motorcycle=50mph \n" ); document.write( "---------------------------------------------------------------------------- \n" ); document.write( "two people working together can do a job in 3 hrs. How long will it take the slower person to do the same job if one of them is 3 times as fast as the other?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "together=1/3 (of the job in an hour) \n" ); document.write( "one person=x \n" ); document.write( "other person=3x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x+3x=1/3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Combine like terms \n" ); document.write( "4x=1/3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Divide both sides by 4 \n" ); document.write( "x=1/12\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1/12 of the job in one hour, so the whole job in 12 hours.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: The slower person can do the job alone in 12 hours. \n" ); document.write( "* The faster person can do the job alone in 4 hours. \n" ); document.write( " |