document.write( "Question 22848: It takes Billy 2 hours longer than Reena to do a certain job. They worked together for 2 hours; then Reena left and Billy finished the job in 1 hour. How long would it take each of them to do the job alone ?\r
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document.write( "(this is from Intermediate Algebra, 7th ed. Jerome Kaufmann/Karen Schwitters, pg 330, problem 42, Quadratic Equations and Inequalities...only one I couldn't get) \n" );
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Algebra.Com's Answer #11236 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! LET TIME TAKEN BY REENA ALONE TO DO 1 JOB =X HRS \n" ); document.write( "BILLY ALONE TAKES 2 HRS. MORE =X+2 \n" ); document.write( "SO REENA CAN DO ALONE IN 1 HOUR =1/X JOB \n" ); document.write( "BILLY CAN DO ALONE IN 1 HOUR =1/(X+2) JOB \n" ); document.write( "TOGETHER THEY CAN DO IN 1 HR.=(1/X)+(1/(X+2)) JOB \n" ); document.write( "IN 2 HRS TOGETHER THEY CAN DO =2*{(1/X)+(1/(X+2))} JOB \n" ); document.write( "NOW REENA LEFT AND BILL ONLY WORKED FOR 1 HOUR = BILLY ALONE DOES 1/(X+2) JOB IN 1 HOUR \n" ); document.write( "SO TOTAL JOB DONE =2*{(1/X)+(1/(X+2))}+(1/(X+2)) JOB..BUT THIS COMPLETED THE 1 JOB .SO \n" ); document.write( "2*{(1/X)+(1/(X+2))}+(1/(X+2)) =1 \n" ); document.write( "2/(X)+2/(X+2)+1/(X+2)=1..L.C.M IS (X)(X+2) \n" ); document.write( "{2(X+2)+2(X)+1(X)}/(X)(X+2)=1 \n" ); document.write( "MULTIPLYING BY LCM (X)(X+2) BOTH SIDES WE GET \n" ); document.write( "2X+4+2X+X=(X)(X+2)=X^2+2X \n" ); document.write( "5X+4=X^2+2X \n" ); document.write( "X^2+2X-5X-4=0 \n" ); document.write( "X^2-3X-4=0 \n" ); document.write( "X^2-4X+X-4=0 \n" ); document.write( "X(X-4)+(X-4)=0 \n" ); document.write( "(X+1)(X-4)=0 \n" ); document.write( "X-4=0 \n" ); document.write( "X=4 \n" ); document.write( "SO REENA CAN DO THE JOB IN 4 HRS AND BILL CAN DO IN X+2=4+2=6 HRS THE JOB. \n" ); document.write( " |