document.write( "Question 152871: How many positive real solutions are there in f(x) = x^4 + 4x^3 + 6x^2 + 4x – 1
\n" ); document.write( "Apply Descartes' Rule of Signs.
\n" ); document.write( "a. 1
\n" ); document.write( "b. 1 or 2
\n" ); document.write( "c. 4 or 2
\n" ); document.write( "d. 2 or 0
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Algebra.Com's Answer #112348 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Count the sign changes of \"f%28x%29=x%5E4%2B4x%5E3%2B6x%5E2%2B4x-1\"\r
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\n" ); document.write( "\n" ); document.write( "From \"x%5E4\" to \"4x%5E3\", there is no change in sign\r
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\n" ); document.write( "\n" ); document.write( "From \"4x%5E3\" to \"6x%5E2\", there is no change in sign\r
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\n" ); document.write( "\n" ); document.write( "From \"6x%5E2\" to \"4x\", there is no change in sign\r
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\n" ); document.write( "\n" ); document.write( "From \"4x\" to \"-1\", there is a sign change from positive to negative \r
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\n" ); document.write( "\n" ); document.write( "So there is 1 sign change for the expression \"f%28x%29=x%5E4%2B4x%5E3%2B6x%5E2%2B4x-1\". \r
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\n" ); document.write( "\n" ); document.write( "So there are 1 positive zeros\r
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\n" ); document.write( "\n" ); document.write( "So the answer is a) 1
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