document.write( "Question 152846This question is from textbook Algebra structure and method book 1
\n" ); document.write( ": can you please help me solve and check this problem: (((An investment of $1500 paid interest of $45 during a certain period. how much interest would an investment of $2000 invested at the same rate for the same length of time pay?))) \n" ); document.write( "

Algebra.Com's Answer #112337 by mangopeeler07(462) $\"\"$ $\"About$

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First you must find the rate.\r
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\n" ); document.write( "\n" ); document.write( "What percent of 1500 is 45?\r
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\n" ); document.write( "\n" ); document.write( "45/1500=x/100
\n" ); document.write( "4500=1500x
\n" ); document.write( "3=x\r
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\n" ); document.write( "\n" ); document.write( "45 is 3% of 1500. Now that you know the rate you must apply it to the second monetary value.\r
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\n" ); document.write( "\n" ); document.write( "What is 3% of 2000?\r
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\n" ); document.write( "\n" ); document.write( "x/2000=3/100
\n" ); document.write( "100x=6000
\n" ); document.write( "x=60\r
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\n" ); document.write( "\n" ); document.write( "Answer: $60.00 \n" ); document.write( "

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