document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=152792>Question 152792</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am having problems with problem because of the different start times.  The only problems online I have found with different start times are when the two vehicles are leaving from the same location.\r<BR>\n" );
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document.write( "At noon a train leaves Bridgton heading east at 90 mi/hr to Cogsville, 450 miles away.  At 12:15 pm a train leaves Cogsville heading west to Bridgton at 100 mi/hr.  At what time will they pass each other? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #112306 by </B><A HREF=/tutors/aboutme.mpl?userid=Shelley><B>Shelley(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Shelley><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=112306\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> What I needed to do to start this problem finally hit me.\r<BR>\n" );
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document.write( "1. You need to figure how far Train A travels in 15 minutes. We use this to determine the distance between the two trains when Train B leaves its station at 12:15.\r<BR>\n" );
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document.write( "2.  If 90/4=22.5 then 450-22.5=427.5 miles (This is the distance between Train A and Train B at 12:15\r<BR>\n" );
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document.write( "3.  Now you just plug your numbers into the d=rt formula\r<BR>\n" );
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document.write( "450 - 22.5 = 90t + 100t<BR>\n" );
document.write( "427.5 = 190t<BR>\n" );
document.write( "2.25 = t\r<BR>\n" );
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document.write( "So the time traveled after the 12:15 start time is 2h 15m<BR>\n" );
document.write( "Therefore the time that the trains pass each other will be 2:30 PM\r<BR>\n" );
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