document.write( "Question 152793: how do i turn -5, 4, and 6 into polynomial funtions with rational coeffients in standard form? \n" ); document.write( "
Algebra.Com's Answer #112305 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Since \"-5\", \"4\", and \"6\" are given zeros this means that:\r
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\n" ); document.write( "\n" ); document.write( "\"x=-5\", \"x=4\", and \"x=6\"\r
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\n" ); document.write( "\n" ); document.write( "Get all terms to the left side in each case\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B5=0\", \"x-4=0\", and \"x-6=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B5%29%28x-4%29%28x-6%29=0\" Now use the zero product property in reverse to join the factors.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B5%29%28x%5E2-10x%2B24%29=0\" FOIL\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x%5E2-10x%2B24%29%2B5%28x%5E2-10x%2B24%29=0\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E3-10x%5E2%2B24x%2B5x%5E2-50x%2B120=0\" Distribute again\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E3-5x%5E2-26x%2B120=0\" Combine like terms\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the polynomial with roots of \"-5\", \"4\", and \"6\" is\r
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\n" ); document.write( "\n" ); document.write( "\"y=x%5E3-5x%5E2-26x%2B120\"\r
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\n" ); document.write( "\n" ); document.write( "Notice how if we graph \"y=x%5E3-5x%5E2-26x%2B120\", we can visually verify our answer\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+500%2C+500%2C+-10%2C+10%2C+-50%2C+150%2C+x%5E3-5%2Ax%5E2-26%2Ax%2B120+%29+\" Graph of \"y=x%5E3-5%2Ax%5E2-26%2Ax%2B120\" with roots of \"x=-5\", \"x=4\", and \"x=6\"\r
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