document.write( "Question 22623: Can someone help me solve for y:\r
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document.write( "5(4x + 3) <= -1/2y + 5
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document.write( "20x + 15 <= -1/2y + 5
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document.write( "20x + 15 - 5 <= -1/2y
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document.write( "20x + 10 <= -1/2y
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document.write( "I get lost after this. \n" );
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Algebra.Com's Answer #11230 by rapaljer(4671)![]() ![]() You can put this solution on YOUR website! What you have done so far looks right.\r \n" ); document.write( "\n" ); document.write( "20x + 10 <= -1/2y\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now multiply both sides by -2, which of course reverses the inequality sign:\r \n" ); document.write( "\n" ); document.write( "-2(20x + 10) >= -2(-1/2y) \n" ); document.write( "-40x - 20 >= y\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You probably don't want y on the right side so switch sides, but when you do this reverses the inequality again:\r \n" ); document.write( "\n" ); document.write( "-40x - 20 >= y \n" ); document.write( "y<=-40x-20\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Is that what you wanted to do??\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R^2 at SCC\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |