document.write( "Question 2588: Mary left home at 12 noon and drove to visit her mom who lives 20 miles away. After she arrived she stayed for 2 hours. Afterwards she drove to her friend Sue's house who lives 15 miles from her mom. She arrived at Sue's at 3 oclock. If her speed heading for Sue's was 5 miles per hour faster than her speed going to her mom's, find her average speed on her way to Sue's. \n" ); document.write( "
Algebra.Com's Answer #1123 by kiru_khandelwal(79)![]() ![]() ![]() You can put this solution on YOUR website! Let the speed with which mary goes to her mom place be x \n" ); document.write( "So the speed with which mary goes to her freinds place will be x+5\r \n" ); document.write( "\n" ); document.write( "Mary starts from her home at 12 noon and finally reaches her freinds place at 3'o clock....so total time take by mary is 3 hrs. This 3 hrs also include the time which mary stayed at her mom's place...which is 2 hrs\r \n" ); document.write( "\n" ); document.write( "Now we know that\r \n" ); document.write( "\n" ); document.write( "Time = distance/speed\r \n" ); document.write( "\n" ); document.write( "so time taken by mary to gor from her house to her mom's house will be 20/x \n" ); document.write( "time taken to go from mom's house to friends house will be 15/(x+5)\r \n" ); document.write( "\n" ); document.write( "so total time taken is \n" ); document.write( "20/x + 2 + 15/(x+5)\r \n" ); document.write( "\n" ); document.write( "But total time taken is 3 hrs\r \n" ); document.write( "\n" ); document.write( "so the equation will be\r \n" ); document.write( "\n" ); document.write( "20/x + 2 + 15/(x+5) = 3 \n" ); document.write( "=> 20/x + 15/(x+5) = 1 \n" ); document.write( "=> (20x + 100 + 15x)/x(x+5) = 1 \n" ); document.write( "=> 35x + 100 = x(x+5) \n" ); document.write( "=> 35x + 100 = x^2 + 5x \n" ); document.write( "=> x^2 + 5x - 35x -100 = 0 \n" ); document.write( "=> x^2 -30x - 100 = 0 \n" ); document.write( "=> x = 15 +/-5*sqrt(13) \n" ); document.write( "=> So the speed x will be 15 + 5*sqrt(13). It cant be the other one because speed cannot be negative.\r \n" ); document.write( "\n" ); document.write( "So her speed to her mom's house is 15 + 5*sqrt(13) \n" ); document.write( "and speed to sue's house will be 15 + 5*sqrt(13) + 5 = 20 + 5*sqrt(13) \n" ); document.write( " |