document.write( "Question 152677: When Lee was 3 times as old as kevin. his sister Kate was 27. Kevin was half as old as Kate brother Lee was 38 there ages add to 143 how old are Kevin , Kate and Lee.
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #112287 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
When Lee was 3 times as old as Kevin, his sister Kate was 27. Kevin was half as old as Kate brother Lee was 38 there ages add to 143 how old are Kevin , Kate, and Lee.
\n" ); document.write( ":
\n" ); document.write( "This is really poorly written. Whoever wrote this, should go back to pushing a broom.
\n" ); document.write( ":
\n" ); document.write( "Write an equation for each statement:
\n" ); document.write( ":
\n" ); document.write( "\"When Lee was 3 times as old as kevin.\"
\n" ); document.write( "L = 3Ke
\n" ); document.write( ":
\n" ); document.write( " his sister Kate was 27.
\n" ); document.write( "Ka = 27
\n" ); document.write( ":
\n" ); document.write( "Rewriting the statement to make sense.
\n" ); document.write( "Kevin was half as old as Lee, when he was 38.
\n" ); document.write( "Ke = .5L = 38
\n" ); document.write( "Therefore:
\n" ); document.write( "L = 2 * 38 = 76
\n" ); document.write( ":
\n" ); document.write( ":Find out how many years ago (x) that L = 3Ke:
\n" ); document.write( "76 - x = 3(38-x)
\n" ); document.write( "76 - x = 114 - 3x
\n" ); document.write( "+3x - x = 114 - 76
\n" ); document.write( "2x = 38
\n" ); document.write( "x = 19 years ago
\n" ); document.write( ":
\n" ); document.write( "19 yrs ago L = 57; Ke = 19; (3*19=57); Ka = 27
\n" ); document.write( "Ka age now: 27 + 19 = 46 yrs old
\n" ); document.write( ":
\n" ); document.write( "Now the problems is that 38 + 76 + 46 = 160 not 143\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );