document.write( "Question 152677: When Lee was 3 times as old as kevin. his sister Kate was 27. Kevin was half as old as Kate brother Lee was 38 there ages add to 143 how old are Kevin , Kate and Lee.
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Algebra.Com's Answer #112287 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! When Lee was 3 times as old as Kevin, his sister Kate was 27. Kevin was half as old as Kate brother Lee was 38 there ages add to 143 how old are Kevin , Kate, and Lee. \n" ); document.write( ": \n" ); document.write( "This is really poorly written. Whoever wrote this, should go back to pushing a broom. \n" ); document.write( ": \n" ); document.write( "Write an equation for each statement: \n" ); document.write( ": \n" ); document.write( "\"When Lee was 3 times as old as kevin.\" \n" ); document.write( "L = 3Ke \n" ); document.write( ": \n" ); document.write( " his sister Kate was 27. \n" ); document.write( "Ka = 27 \n" ); document.write( ": \n" ); document.write( "Rewriting the statement to make sense. \n" ); document.write( "Kevin was half as old as Lee, when he was 38. \n" ); document.write( "Ke = .5L = 38 \n" ); document.write( "Therefore: \n" ); document.write( "L = 2 * 38 = 76 \n" ); document.write( ": \n" ); document.write( ":Find out how many years ago (x) that L = 3Ke: \n" ); document.write( "76 - x = 3(38-x) \n" ); document.write( "76 - x = 114 - 3x \n" ); document.write( "+3x - x = 114 - 76 \n" ); document.write( "2x = 38 \n" ); document.write( "x = 19 years ago \n" ); document.write( ": \n" ); document.write( "19 yrs ago L = 57; Ke = 19; (3*19=57); Ka = 27 \n" ); document.write( "Ka age now: 27 + 19 = 46 yrs old \n" ); document.write( ": \n" ); document.write( "Now the problems is that 38 + 76 + 46 = 160 not 143\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |