document.write( "Question 152760: At 5:00 PM a plane leaves an airport and flies due north at 588 km/h. At 6:00 PM a second plane leaves the airport, also flying north but at 732 km/h. When does the second plane overtake the first? \n" ); document.write( "
Algebra.Com's Answer #112279 by nerdybill(7384)\"\" \"About 
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At 5:00 PM a plane leaves an airport and flies due north at 588 km/h. At 6:00 PM a second plane leaves the airport, also flying north but at 732 km/h. When does the second plane overtake the first?
\n" ); document.write( ".
\n" ); document.write( "You need to apply the \"distance formula\":
\n" ); document.write( "d = rt
\n" ); document.write( "where
\n" ); document.write( "d is distance
\n" ); document.write( "r is rate or speed
\n" ); document.write( "t is time
\n" ); document.write( ".
\n" ); document.write( "Let x = amount of time it takes for second plane to catch up to the first plane
\n" ); document.write( ".
\n" ); document.write( "\"distance traveled by plane one\" = \"distance traveled by plane two\"
\n" ); document.write( "588(x+1) = 732(x)
\n" ); document.write( "588x + 588 = 732x
\n" ); document.write( "588 = 144x
\n" ); document.write( "588/144 = x
\n" ); document.write( "4.083 hours = x
\n" ); document.write( "or in terms of hours and minutes:
\n" ); document.write( "4 hrs and .083(60) mins
\n" ); document.write( "4 hrs and 4.98 mins
\n" ); document.write( "or, in terms of hours, minutes and seconds:
\n" ); document.write( "4 hrs, 4 mins and .98(60) seconds
\n" ); document.write( "4 hrs, 4 mins and 59 seconds
\n" ); document.write( ".
\n" ); document.write( "Conclusion:
\n" ); document.write( "6 PM plus 4 hrs, 4 mins and 59 seconds
\n" ); document.write( "is
\n" ); document.write( "10:04:59 PM
\n" ); document.write( " \n" ); document.write( "
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