document.write( "Question 22803: We're rationalizing the demoninator. I'm having difficulty solving this:\r
\n" ); document.write( "\n" ); document.write( "4
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\n" ); document.write( "The Cube root of 3.\r
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Algebra.Com's Answer #11223 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
Before beginning ANY cube root problem, be sure that you know your perfect cubes. That is,
\n" ); document.write( "\"2%5E3=8\", \"3%5E3=+27\", \"4%5E3=+64\", \"5%5E3=125\"\r
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\n" ); document.write( "\n" ); document.write( "Now, \"4%2F+root%283%2C3%29\"\r
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\n" ); document.write( "\n" ); document.write( "The idea is to somehow get the number in that radical in the denominator up to a perfect cube. When you think of the 3 inside the cube root sign, what perfect cube comes to mind associated with 3? The answer should be 27.\r
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\n" ); document.write( "\n" ); document.write( "You need to get that denominator from 3 up to 27, by multiplying it by 9. In other words you must multiply the numerator and denominator by the cube root of 9.\r
\n" ); document.write( "\n" ); document.write( "\"%284%2F+root%283%2C3%29+%29%2A%28%28root%283%2C9%29%29%2F%28root%283%2C9%29%29%29\"\r
\n" ); document.write( "\n" ); document.write( "Multiply numerator times numerator and denominator times denominator:
\n" ); document.write( "= \"%284%2A+root%283%2C9%29+%29%2F%28root%283%2C27%29%29%29\"= \"%284%2A+root+%283%2C9%29%29%2F3\"= \"%284%2F3%29%2A+root%283%2C9%29\"\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC\r
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