document.write( "Question 152555: Franklin bikes from A to B at 25km/h.
\n" ); document.write( "He returns by car at 75km/h.
\n" ); document.write( "The bike trip is 2 hours longer than the car trip.
\n" ); document.write( "How far is it from A to B? \n" ); document.write( "
Algebra.Com's Answer #112228 by ankor@dixie-net.com(22740)\"\" \"About 
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Franklin bikes from A to B at 25km/h.
\n" ); document.write( "He returns by car at 75km/h.
\n" ); document.write( "The bike trip is 2 hours longer than the car trip.
\n" ); document.write( "How far is it from A to B?
\n" ); document.write( ":
\n" ); document.write( "Let t = car time
\n" ); document.write( "then
\n" ); document.write( "(t+2) = bike time
\n" ); document.write( ":
\n" ); document.write( "The two trips are the same distance; write a dist equation: dist = speed * time
\n" ); document.write( "Car dist = Bike dist
\n" ); document.write( "75t = 25(t+2)
\n" ); document.write( "75t = 25t + 50
\n" ); document.write( "75t - 25t = 50
\n" ); document.write( "50t = 50
\n" ); document.write( "t = 1 hr is the car time, then 3 hrs is the bike time, obviously.
\n" ); document.write( ":
\n" ); document.write( "Find the dist:
\n" ); document.write( "75* 1 = 75 km
\n" ); document.write( "or
\n" ); document.write( "3*25 = 75 km
\n" ); document.write( " \n" ); document.write( "
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