document.write( "Question 152557: Kara floats from A to B at 6 km/h.
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document.write( "She returns by motorboat at 18km/h.
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document.write( "The float trip is 4 hours longer than the motorboat trip.
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document.write( "How far is it from A to B? \n" );
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Algebra.Com's Answer #112224 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Kara floats from A to B at 6 km/h. \n" ); document.write( "She returns by motorboat at 18km/h. \n" ); document.write( "The float trip is 4 hours longer than the motorboat trip. \n" ); document.write( "How far is it from A to B? \n" ); document.write( ": \n" ); document.write( "We know the speed of the current = 6 km/hr \n" ); document.write( "We know the speed of the boat on the return trip; = 18 km/hr (not in still water) \n" ); document.write( ": \n" ); document.write( "Let t = time of the boat trip \n" ); document.write( "then \n" ); document.write( "(t+4) = time floating \n" ); document.write( ": \n" ); document.write( "Distance of both trip is the same, write a dist equation; dist = speed * time \n" ); document.write( ": \n" ); document.write( "18t = 6(t+4) \n" ); document.write( "18t = 6t + 24 \n" ); document.write( "18t - 6t = 24 \n" ); document.write( "12t = 24 \n" ); document.write( "t = \n" ); document.write( "t = 2 hrs on the boat, and 6 hr on the river \n" ); document.write( ": \n" ); document.write( "Find the distance \n" ); document.write( "6 * 6 = 36 km A to B \n" ); document.write( "or \n" ); document.write( "18 * 2 = 36 km B to A \n" ); document.write( " \n" ); document.write( " |