document.write( "Question 152596: Mitchel drove to a friend at a rate of 40 miles/hr. He returned by the same route at a rate of 45 miles/hr.The driving time for the round trip was 4 hours.What is the distance Mitchel travelled ? \n" ); document.write( "
Algebra.Com's Answer #112161 by Earlsdon(6294)\"\" \"About 
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You can use the distance formula: \"d+=+r%2At\" where: d = distance, r = rate (speed), and t = time of travel.
\n" ); document.write( "For the outbound trip:
\n" ); document.write( "\"d%5B1%5D+=+r%5B1%5D%2At%5B1%5D\"
\n" ); document.write( "For the return trip:
\n" ); document.write( "\"d%5B2%5D+=+r%5B2%5D%2At%5B2%5D\"
\n" ); document.write( "In this problem, \"d%5B1%5D+=+d%5B2%5D\" and \"t%5B1%5D%2Bt%5B2%5D+=+4\", so you can write:
\n" ); document.write( "\"r%5B1%5D%2At%5B1%5D+=+r%5B2%5D%2At%5B2%5D\"
\n" ); document.write( "\"r%5B1%5D+=+40\" and \"r%5B2%5D+=+45\" These are given, so...
\n" ); document.write( "\"40%2At%5B1%5D+=+45%2At%5B2%5D\" Substitute: \"t%5B2%5D+=+4-t%7B1%5D\"
\n" ); document.write( "\"40%2At%5B1%5D+=+45%2A%284-t%5B1%5D%29\" Simplify and solvefor \"t%5B1%5D\"
\n" ); document.write( "\"40%2At%5B1%5D+=+180-45%2At%5B1%5D\" Add \"45%2At%5B1%5D\" to both sides.
\n" ); document.write( "\"85%2At%5B1%5D+=+180\" Divide both sides by 85.
\n" ); document.write( "\"t%5B1%5D+=+2.12\"hours.
\n" ); document.write( "Now you can calculate the one-way distance, \"d%5B1%5D\"
\n" ); document.write( "\"d%5B1%5D+=+40%2At%5B1%5D\"
\n" ); document.write( "\"d%5B1%5D+=+40%2A2.12\"
\n" ); document.write( "\"d%5B1%5D+=+84.8\"miles.
\n" ); document.write( "This should be equal to \"d%5B2%5D\"...let's see if it is:
\n" ); document.write( "\"d%5B2%5D+=+r%5B2%5D%2At%5B2%5D\" Substitute \"r%5B2%5D+=+45\" and \"t%5B2%5D+=+4-2.12\"=\"1.88\"
\n" ); document.write( "\"d%5B2%5D+=+45%2A1.88\"
\n" ); document.write( "\"d%5B2%5D+=+84.6\"miles.
\n" ); document.write( "Michael travelled \"d%5B1%5D%2Bd%5B2%5D+=+84.8%2B84.6\"=\"169.4\"miles.
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