document.write( "Question 152486: Hi,\r
\n" ); document.write( "\n" ); document.write( "How would I solve the following: Applications of Linear Equations \r
\n" ); document.write( "\n" ); document.write( "An express and local train leave Gray’s Lake at 3 P.M. and head for Chicago 50 miles away. The express travels twice as fast as the local, and arrives 1 hour ahead of it. Find the speed of each train. \r
\n" ); document.write( "\n" ); document.write( "Thank you so much for your help.\r
\n" ); document.write( "\n" ); document.write( "K.\r
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Algebra.Com's Answer #112129 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
An express and local train leave Gray’s Lake at 3 P.M. and head for Chicago 50 miles away. The express travels twice as fast as the local, and arrives 1 hour ahead of it. Find the speed of each train.
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\n" ); document.write( "Let s = speed of the local train
\n" ); document.write( "then
\n" ); document.write( "2s = speed of the express
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\n" ); document.write( "Write a time equation: Time = \"dist%2Fspeed\"
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\n" ); document.write( "Local time - express time = 1 hr
\n" ); document.write( "\"50%2Fs\" - \"50%2F%282s%29\" = 1
\n" ); document.write( "Multiply equation by 2s to get rid of the denominators
\n" ); document.write( "2s*\"50%2Fs\" - 2s*\"50%2F%282s%29\" = 2s(1)
\n" ); document.write( "Results
\n" ); document.write( "2(50) - 50 = 2s
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\n" ); document.write( "100 - 50 = 2s
\n" ); document.write( "s = \"50%2F2\"
\n" ); document.write( "s = 25 mph speed of the local, obviously, 50 mph is speed of express
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\n" ); document.write( "Check solution in our time equation:
\n" ); document.write( "\"50%2F25\" - \"50%2F%2850%29\" = 1
\n" ); document.write( "2 - 1 = 1
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\n" ); document.write( "Pretty easy, right?
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