document.write( "Question 152486: Hi,\r
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document.write( "How would I solve the following: Applications of Linear Equations \r
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document.write( "An express and local train leave Gray’s Lake at 3 P.M. and head for Chicago 50 miles away. The express travels twice as fast as the local, and arrives 1 hour ahead of it. Find the speed of each train. \r
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document.write( "Thank you so much for your help.\r
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document.write( "K.\r
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Algebra.Com's Answer #112129 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! An express and local train leave Gray’s Lake at 3 P.M. and head for Chicago 50 miles away. The express travels twice as fast as the local, and arrives 1 hour ahead of it. Find the speed of each train. \n" ); document.write( "; \n" ); document.write( "Let s = speed of the local train \n" ); document.write( "then \n" ); document.write( "2s = speed of the express \n" ); document.write( ": \n" ); document.write( "Write a time equation: Time = \n" ); document.write( ": \n" ); document.write( "Local time - express time = 1 hr \n" ); document.write( " \n" ); document.write( "Multiply equation by 2s to get rid of the denominators \n" ); document.write( "2s* \n" ); document.write( "Results \n" ); document.write( "2(50) - 50 = 2s \n" ); document.write( ": \n" ); document.write( "100 - 50 = 2s \n" ); document.write( "s = \n" ); document.write( "s = 25 mph speed of the local, obviously, 50 mph is speed of express \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution in our time equation: \n" ); document.write( " \n" ); document.write( "2 - 1 = 1 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Pretty easy, right? \n" ); document.write( " |