document.write( "Question 152445: Half of Henry's age added to 1/3 od Daisy's age is 11 years.
\n" ); document.write( "Six years from now, the sum of their ages will be 40 years.
\n" ); document.write( "How old is each? \n" ); document.write( "
Algebra.Com's Answer #112121 by checkley77(12844)\"\" \"About 
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.5H+D/3=11
\n" ); document.write( "(H+6)+(D+6)=40
\n" ); document.write( "H+D+12=40
\n" ); document.write( "H+D=40-12
\n" ); document.write( "H+D=28
\n" ); document.write( "H=28-D NOW REPLACE H BY (28-D) IN THE FIRST EQUATION
\n" ); document.write( ".5(28-D)+D/3=11
\n" ); document.write( "14-.5D+D/3=11
\n" ); document.write( "-.5D+D/3=11-14
\n" ); document.write( "(3*-.5D+D)/3=-3
\n" ); document.write( "(-1.5D+D)/3=-3
\n" ); document.write( "-.5D=-9
\n" ); document.write( "D=-9/-.5
\n" ); document.write( "D=18 ANSWER FOR DAISY'S AGE NOW.
\n" ); document.write( "H+18+12=40
\n" ); document.write( "H+30=40
\n" ); document.write( "H=40-30
\n" ); document.write( "H=10 AGE OF HENRY NOW.
\n" ); document.write( "PROOF:
\n" ); document.write( ".5*10+18/3=11
\n" ); document.write( "5+6=11
\n" ); document.write( "11=11\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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