document.write( "Question 152520: Q: e^(2x+5)=40
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document.write( "its pretty simple i think, this is what i've figured out.
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document.write( "ln(e^(2x+5))=ln(40)
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document.write( "2x+5=ln(40)
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document.write( "2x+5 = 3.688
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document.write( "2x = -2.688
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document.write( "x = -1.344\r
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document.write( "im not sure if thats right, i didnt really pay attention in logs,and e's. \n" );
document.write( "
Algebra.Com's Answer #112111 by Fombitz(32388) You can put this solution on YOUR website! Quickest way to check is to plug your solution into the equation and make sure it solves it. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Oops, there's a problem. \n" ); document.write( "You paid attention for logarithms but not during subtraction. \n" ); document.write( "Your thinking and approach to the problem are clear. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "It should be, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Checking, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Close enough. \n" ); document.write( " |