document.write( "Question 152498: Three consecutive odd integers are such that the square of the third is 264 more than the square of the second. Find the three integers. \n" ); document.write( "
Algebra.Com's Answer #112090 by mangopeeler07(462)\"\" \"About 
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consecutive odd integers= x, x+2, x+4
\n" ); document.write( "(x+4)^2=(x+2)^2+264\r
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\n" ); document.write( "\n" ); document.write( "Simplify
\n" ); document.write( "x^2+8x+16=x^2+4x+4+264\r
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\n" ); document.write( "\n" ); document.write( "Combine like terms on each side
\n" ); document.write( "x^2+8x+16=x^2+4x+268\r
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\n" ); document.write( "\n" ); document.write( "Subtract 4x from both sides
\n" ); document.write( "x^2+4x+16=x^2+268\r
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\n" ); document.write( "\n" ); document.write( "Subtract 268 from both sides
\n" ); document.write( "x^2+4x-252=x^2\r
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\n" ); document.write( "\n" ); document.write( "Subtract x^2 from both sides
\n" ); document.write( "4x-252=0\r
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\n" ); document.write( "\n" ); document.write( "Add 252 to both sides
\n" ); document.write( "4x=252\r
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\n" ); document.write( "\n" ); document.write( "Divide both sides by 4
\n" ); document.write( "x=63\r
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\n" ); document.write( "\n" ); document.write( "consecutive odd integers= x, x+2, x+4
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\n" ); document.write( "Answer: 63, 65, and 67
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