document.write( "Question 152487: Hi,\r
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document.write( "How would I solve the following: Applications of Linear Equations \r
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document.write( "Walt made an extra $9000 last year from a part-time job. He invested part of the money at 9% and the rest at 8%. He made a total of $770 in interest. How much was invested at 8%?\r
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document.write( "Thank you for taking the time to help me.\r
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document.write( "Sally \n" );
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Algebra.Com's Answer #112076 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! G'day Sally;\r \n" ); document.write( "\n" ); document.write( "Let x = the amount invested at 8% and the remainder ($9000-x) is invested at 9% \n" ); document.write( "The amount of interest earned on these amounts can be expressed as: \n" ); document.write( "x(0.08) This is amount earned at 8%. \n" ); document.write( "($9000-x)(0.09) This is the amount earned at 9% \n" ); document.write( "The sum (+) of these two amounts is given as $770.00, so you can write the equation to solve for x, the amount invested at 8% \n" ); document.write( "(0.08)x + (0.09)($9000-x) = $770 Simplify and solve for x. \n" ); document.write( "0.08x + $810 - 0.09x = $770 Subtract $810 from both sides. \n" ); document.write( "0.08x-0.09x = -$40 Combine the x's on the left side. \n" ); document.write( "-0.01x = -$40 Finally, divide both sides by -0.01 to get x by itself. \n" ); document.write( "x = $4000 \n" ); document.write( "So $4000 was invested at 8% and $9000-$4000 = $5000 was invested at 9%\r \n" ); document.write( "\n" ); document.write( "Let's check the solution: \n" ); document.write( "0.08($4000) + 0.09($5000) = $320 + $450 = $770 The total interest earned. \n" ); document.write( " |