document.write( "Question 152429This question is from textbook
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Algebra.Com's Answer #112067 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
I'm having problems trying to figure out this math problem. I'm stuck and no matter what i do the answer just does not come out right. the problem is
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document.write( "\"0.96y-.079=+0.32y=0.46\"\r\n" );
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document.write( "Unfortunately, there is a typo because there \r\n" );
document.write( "are two equal signs.  I will assume one of \r\n" );
document.write( "them must have been supposed to be a plus sign \r\n" );
document.write( "and you neglected to hold down the Shift key.\r\n" );
document.write( "So your problem was either:\r\n" );
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document.write( "\"0.96y-0.079=+0.32y%2B0.46\" or \"0.96y-0.079%2B+0.32y=0.46\"\r\n" );
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document.write( "I'll assume it was the first:\r\n" );
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document.write( "\"0.96y-0.079=+0.32y%2B0.46\"\r\n" );
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document.write( "Since one of the decimals \"0.079\" shows three\r\n" );
document.write( "decimal places put a \"0\" on the end of the other\r\n" );
document.write( "decimals so they will also have three decimal\r\n" );
document.write( "places:\r\n" );
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document.write( "\"0.960y-0.079=+0.320y%2B0.460\"\r\n" );
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document.write( "Now, in each term, move the decimal three\r\n" );
document.write( "places to the right, so they will all become\r\n" );
document.write( "whole numbers:\r\n" );
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document.write( "\"960y-79=320y%2B460\"\r\n" );
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document.write( "Add \"-320y\" to both sides:\r\n" );
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document.write( "\"640y-79=460\"\r\n" );
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document.write( "Add \"79\" to both sides:\r\n" );
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document.write( "\"640y=539\"\r\n" );
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document.write( "Divide both sides by \"640\":\r\n" );
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document.write( "\"640y%2F640=539%2F640\"\r\n" );
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document.write( "Cancel the \"640\"'s\r\n" );
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document.write( "\"cross%28640%29y%2Fcross%28640%29=539%2F640\" \r\n" );
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document.write( "\"y=539%2F640\"\r\n" );
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document.write( "\"y=0.8421875\"\r\n" );
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document.write( "Round to 3 decimal places\r\n" );
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document.write( "\"y=0.842\"\r\n" );
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document.write( "Edwin
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