document.write( "Question 152483: Your organization is planning a conference with 193 people in attendance that need transportation. There are 8 drivers available and 2 types of vehicles, buses and SUV’s . The bus seats 51 people each. The SUV seats 8 people each. How many buses and SUVs will be needed?\r
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document.write( "Let b= # of buses\r
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document.write( "Let s= SUVs\r
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document.write( "Drivers s+b =8\r
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document.write( "People 51b + 8b = 193\r
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Algebra.Com's Answer #112058 by vleith(2983)![]() ![]() ![]() You can put this solution on YOUR website! You have one equation in error. \n" ); document.write( "People 51b + 8b = 193 \n" ); document.write( "Should be \n" ); document.write( "People 51b + 8s = 193\r \n" ); document.write( "\n" ); document.write( "Now s+b=8 \n" ); document.write( "s = 8-b\r \n" ); document.write( "\n" ); document.write( "51b + 8(8-b) = 193 \n" ); document.write( "64 + 43b = 193 \n" ); document.write( "43b = 129 \n" ); document.write( "b = 3 \n" ); document.write( "That makes s = 5\r \n" ); document.write( "\n" ); document.write( "What is interesting in this problem is that you are not told to use all the drivers. So, we could use 4 buses and move them all. That saves 4 drivers to so something else. Assuming the cost for gas for one b is less than 4 SUVs, give the other 4 drivers something better to do.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |