document.write( "Question 152465: How many pints of a 9% cleaning solution must be mixed with 10 pints of a 13%
\n" ); document.write( "cleaning solution to give a 11% solution? \n" ); document.write( "

Algebra.Com's Answer #112055 by ptaylor(2198) $\"\"$ $\"About$

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Let x=amount of 9% solution needed\r
\n" ); document.write( "\n" ); document.write( "Now we know that the amount of pure cleaning solution in the 9% mixture (0.09x) plus the amount of pure cleaning solution in the 13% mixture (0.13*10) has to equal the amount of pure cleaning solution in the final mixture (0.11(10+x)). So our equation to solve is:\r
\n" ); document.write( "\n" ); document.write( "0.09x+0.13*10=0.11(10+x) get rid of parens and simplify\r
\n" ); document.write( "\n" ); document.write( "0.09x+1.3=1.1+0.11x subtract 1.1 and also 0.09x from each side\r
\n" ); document.write( "\n" ); document.write( "0.09x-0.09x+1.3-1.1=1.1-1.1+0.11x-0.09x collect like terms\r
\n" ); document.write( "\n" ); document.write( "0.2=0.02x divide each side by 0.02
\n" ); document.write( "x=10 pints----------------------------------amount of 9% solution needed\r
\n" ); document.write( "\n" ); document.write( "CK\r
\n" ); document.write( "\n" ); document.write( "0.09*10+0.13*10=0.11*20
\n" ); document.write( "0.9+1.3=2.2
\n" ); document.write( "2.2=2.2\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( "

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