document.write( "Question 17286: I have a pocket full of change composed of pennies, nickels, dimes, and quarters. There are four more nickels then pennies.there are twice as many quarters as pennies and four less dimes than quarters.All of the coins add up to 3.60. How many of each type of coins do i have? \n" ); document.write( "
Algebra.Com's Answer #11205 by stanbon(75887)\"\" \"About 
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Let # of pennies be \"x\".
\n" ); document.write( "Then # of nickels = \"x+4\"
\n" ); document.write( "And # of quarters = 2x
\n" ); document.write( "And # of dimes = 2x-4
\n" ); document.write( "Value of pennies is (1)x cents
\n" ); document.write( "Value of nickels is (5)(x+4) = 5x+20 cents
\n" ); document.write( "Value of quarters = (25)2x = 50x cents
\n" ); document.write( "Value of dimes is (10)(2x-4)= 20x-40 cents
\n" ); document.write( "Equation:
\n" ); document.write( "Value of the coins is 360 cents
\n" ); document.write( " x + 5x+ 20+ 50x + 20x -40 = 360
\n" ); document.write( " 76x - 20 = 360
\n" ); document.write( " 76x = 380
\n" ); document.write( " x = 5 (number of pennies)
\n" ); document.write( " x + 4 = 9 (number of nickels)
\n" ); document.write( " 2x = 10(number of quarters)
\n" ); document.write( " 2x-4 = 6 (number of dimes)
\n" ); document.write( " \n" ); document.write( "
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