document.write( "Question 152422: SUPPOSE THAT YOU HAVE AN UNLIMITED SUPPLY OF 5 CENT STAMPS AND 11 CENT STAMPS. YOU CAN MAKE EXACT POSTAGE OF 21 CENT WITH 2-5 CENT STAMPS AND 1-11 CENT STAMP. hOWEVER YOU CANNOT MAKE EXACT POSTAGE OF 23 CENTS BY USING ONLY 5 CENT STAMPS AND 11 CENT STAMPS. WHAT IS THE GREATEST AMOUNT OF EXACT POSTAGE YOU CANNOT MAKE BY USING THESE STAMPS? \n" ); document.write( "
Algebra.Com's Answer #112045 by bucky(2189)![]() ![]() ![]() You can put this solution on YOUR website! An interesting problem to think about and to use in developing an awareness of numbers. \n" ); document.write( ". \n" ); document.write( "Let's begin by thinking about the first 10 numbers ... 1 through 10 \n" ); document.write( ". \n" ); document.write( "In this group of 10 numbers, by using 5 and 11 you can only make the numbers 5 (one 5 cent \n" ); document.write( "stamp) and 10 (two 5 cent stamps). If you think about it, you will now be able to make any \n" ); document.write( "number that ends in 5 or 0 by just adding a series of 10 (two fives) to the number 5 \n" ); document.write( "(one 5 cent stamp) or a series of 10 to the number 10. For example, 15 can be made by \n" ); document.write( "adding two 5 cent stamps to a 5, 25 can be made by adding four 5 cents stamps to a 5, \n" ); document.write( "35 can be made by adding six 5 cent stamps to a 5, and so on. Similarly, you can make \n" ); document.write( "any number that ends in a zero, by adding a series of 2 fives (that is 10 cents) to \n" ); document.write( "two fives ... 20 would be two 5 cent stamps plus two more 5 cent stamps; 30 would be \n" ); document.write( "two 5 cent stamps plus four more 5 cent stamps, forty would be two 5 cent stamps plus \n" ); document.write( "six more 5 cent stamps; and so on. \n" ); document.write( ". \n" ); document.write( "Now let's think about the next 10 numbers ... 11 through 20 \n" ); document.write( ". \n" ); document.write( "In this group of 10 numbers, by using 5 and 11 you can make the numbers 11 (one 11 cent \n" ); document.write( "stamp); 15 (three 5 cent stamps); 16 (one 11 cent stamp and one 5 cent stamp); and 20 \n" ); document.write( "(four 5 cent stamps). So in this group of 10 numbers we have 11, 15, 16, and 20. Using our \n" ); document.write( "previous method of just adding groups of 10 to these numbers, we can now extend this series \n" ); document.write( "to any number that ends in 1, 5, 6, or 0. As examples, 21 would be an 11 cent stamp and \n" ); document.write( "two 5 cent stamps, 31 would be an 11 cent stamp and four 5 cent stamps, 41 would be \n" ); document.write( "an 11 cent stamp and six 5 cent stamps, and so on. Similarly, 26 would be an 11 cent stamp \n" ); document.write( "plus a 5 cent stamp plus two more 5 cent stamps and 36 would be an 11 cent stamp plus \n" ); document.write( "a 5 cent stamp plus 4 more 5 cent stamps. And so on. \n" ); document.write( ". \n" ); document.write( "In the next group of 10 numbers ... 21 through 30 ... we have seen that we can represent \n" ); document.write( "21 (an 11 cent stamp plus two 5 cent stamps) and 25 (five 5-cent stamps) and 26 (two 11 cent \n" ); document.write( "stamps plus one 5 cent stamp) and 30 (six 5 cent stamps). But we can also represent \n" ); document.write( "22 (two 11 cent stamps) and 26 (an 11 cent stamp and three 5 cent stamps) and 27 (two 11 \n" ); document.write( "cent stamps plus one 5 cent stamp). So in this series of numbers we can represent \n" ); document.write( "21, 22, 25, 26, 27, and 30. Therefore, by adding pairs of 5 cent stamps to these numbers \n" ); document.write( "we can now represent any number ending in 1, 2, 5, 6, 7, and 0. \n" ); document.write( ". \n" ); document.write( "In the series of 31 through 40 we will add the capability of 33 (three 11 cent stamps) \n" ); document.write( "and 38 (three 11 cent stamps and a 5 cent stamp). This means the series from 31 to 40 \n" ); document.write( "not only contains the numbers 31, 32, 35, 36, 37, and 40 but it also contains the numbers \n" ); document.write( "33 and 38. So this series consists of 31, 32, 33, 35, 36, 37, 38, and 40. It is missing the \n" ); document.write( "two numbers 34 and 39. \n" ); document.write( ". \n" ); document.write( "Now let's go to the numbers in the series 41 through 50. By adding two 5 cent stamps to each \n" ); document.write( "of the numbers in the series 31 through 40, we can see that we can represent 41, 42, 43, \n" ); document.write( "45, 46, 47, 48, and 50. But we can also represent 44 with four 11 cent stamps and 49 \n" ); document.write( "with four 11 cent stamps plus a 5 cent stamp. Therefore, in this series we can represent all \n" ); document.write( "the numbers ... 41, 42, 43, 44, 45, 46, 47, 48, 49, and 50. \n" ); document.write( ". \n" ); document.write( "From that point on we can represent any number by just adding some number of 10 cents (two 5 \n" ); document.write( "cent stamps) to each number in the series 41 through 50. Want to represent 1008? Just \n" ); document.write( "recognize that this number ends in 8 so it is the representation of 48 (four 11 cent stamps \n" ); document.write( "plus a 5 \n" ); document.write( "cent stamp for a total of 48 cents) and you add to that 48 cents 960 cents more (192 five \n" ); document.write( "cent stamps) to get 1008 cents of postage. \n" ); document.write( ". \n" ); document.write( "So the biggest number that we could not represent using a combination of 11 cent and \n" ); document.write( "5 cent stamps was 39. \n" ); document.write( ". \n" ); document.write( "Hope this helps you to understand the problem a little better. If you think about this \n" ); document.write( "a little it will probably begin to make some sense. It's easier to do than it is to \n" ); document.write( "explain it, that's for sure. \n" ); document.write( ". \n" ); document.write( " |