document.write( "Question 152418This question is from textbook algebra1
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document.write( ": Without grouping symbols, the expressionhas a value of 58. Insert grouping symbols in the expression 2x3^3+4 to produce the indicated values,
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document.write( "a.62 b.220 c.4374 d.279,936 \n" );
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Algebra.Com's Answer #112025 by bucky(2189)![]() ![]() ![]() You can put this solution on YOUR website! Start with: \n" ); document.write( ". \n" ); document.write( "2*3^3+7 \n" ); document.write( ". \n" ); document.write( "Given example grouping: \n" ); document.write( ". \n" ); document.write( "2*(3^3)+ 4 = 2*(27) + 4 = 54 + 4 = 58 which is the example the problem gave without grouping \n" ); document.write( ". \n" ); document.write( "Next grouping: \n" ); document.write( ". \n" ); document.write( "2(3^3 + 4) = 2(27 + 4) = 2(31) = 62 <=== answer to part a \n" ); document.write( ". \n" ); document.write( "Next grouping: \n" ); document.write( ". \n" ); document.write( "(2*3)^3 + 4 = 6^3 + 4 = 216 + 4 = 220 <=== answer for part b \n" ); document.write( ". \n" ); document.write( "Next grouping: \n" ); document.write( ". \n" ); document.write( "2*(3^(3+4)) = 2*(3^7) = 2*2187 = 4374 <=== answer for part c \n" ); document.write( ". \n" ); document.write( "Final grouping: \n" ); document.write( ". \n" ); document.write( "(2*3)^(3+4) = (6)^(3+4) = 6^7 = 279,936 <=== answer for part d \n" ); document.write( ". \n" ); document.write( "Hope this helps you to understand the concept of grouping. The rules of grouping basically \n" ); document.write( "involve: \n" ); document.write( ". \n" ); document.write( "I. First due the operations inside parentheses. Inside each set of parentheses follow rules \n" ); document.write( "II, III, and IV below. \n" ); document.write( "II. Second do the exponents \n" ); document.write( "III. Then do the multiplications and divisions from left to right as you encounter them. \n" ); document.write( "IV. Finally do the additions and subtractions in order from left to right as you encounter them. \n" ); document.write( ". \n" ); document.write( "It just takes some practice to get the hang of it. \n" ); document.write( " \n" ); document.write( " |