document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=152357>Question 152357</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Word Problems are so hard for me. I can do them with a calulator, but to write them out in algebriac terms and answering them, I am at a loss.<BR>\n" );
document.write( "Here is the word problem:<BR>\n" );
document.write( "Samantha needs 20 quarts of 50% antifreeze solution in her radiator. She plans to obtain this by nixing some pure antifreeze with an appropriate amount of 40% antifreeze solution. How many quarts of each should she use?\r<BR>\n" );
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document.write( "I was thinking 40x . 50 = 20 or maybe 50x + (40 x 20)<BR>\n" );
document.write( "I am so new at math, and it is just confusing me to no end!I don't know how to write it, but normally if it's written out I can answer the problem if it's not too complicated.<BR>\n" );
document.write( "I would really appreciate any help on this. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #112000 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=112000\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Some times, with mixture problems such as this one, it might be a little easier if you think in terms of just the antifreeze rather than the mixture.<BR>\n" );
document.write( "You are told that Samantha needs 20 quarts of 50% antifreeze. First, change the percentage to its decimal equavalent (50% = 50/100 = 0.5).<BR>\n" );
document.write( "Now 50% of 20 quarts of antifreeze mixture is really 0.5 (20) = 10 quarts of pure antifreeze.<BR>\n" );
document.write( "The amount of 40% antifreeze mixture to be added is (20-x) quarts, that is this is the amount, added to the x quarts of pure antifreeze to get the 20 quarts.<BR>\n" );
document.write( "Now let x = the amount of pure (100% = 1) antifreeze to be added to (20-x) quarts of 40% antifreeze mixture.<BR>\n" );
document.write( "The amount of 40% antifreeze mixture is 0.4(20-x) quarts of antifreeze.<BR>\n" );
document.write( "Now you can write an equation to solve for x, the number of quarts of pure antifreeze that Samantha needs.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+%2B+0.4%2820-x%29+=+0.5%2820%29 ALIGN=MIDDLE  ALT=\"x+%2B+0.4%2820-x%29+=+0.5%2820%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Perform the indicated multiplication.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+%2B+8+-+0.4x+=+10 ALIGN=MIDDLE  ALT=\"x+%2B+8+-+0.4x+=+10\"   DISABLED_style= \"max-width:90%; height:auto;\" > Combine the x's<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0.6x+%2B+8+=+10 ALIGN=MIDDLE  ALT=\"0.6x+%2B+8+=+10\"   DISABLED_style= \"max-width:90%; height:auto;\" > Subtract 8 from both sides.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0.6x+=+2 ALIGN=MIDDLE  ALT=\"0.6x+=+2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Finally, didvide both sides by 0.6 to get x by itself.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+3.33 ALIGN=MIDDLE  ALT=\"x+=+3.33\"   DISABLED_style= \"max-width:90%; height:auto;\" > or x = 3 1/3<BR>\n" );
document.write( "So Samantha needs to mix 3 1/3 quarts of pure antifreeze with 20-x = 20-3 1/3 = 16 2/3 quarts of 40% antifreeze mixture to obtain 20 quarts of 50% antifreeze mixture.. </SPAN>\n" );
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