document.write( "Question 152350: Find the measure of an angle if its measure is four times the measure of its complement? \n" ); document.write( "

Algebra.Com's Answer #111997 by jojo14344(1513) $\"\"$ $\"About$

You can put this solution on YOUR website!
We know complement angles form $\"90+degrees\"$
\n" ); document.write( "Let's make 2 angles as $\"angleA\"$ & it's complement as $\"angleB\"$
\n" ); document.write( "So, $\"%28angleA%29%2B%28angleB%29=90\"$ -----------> working eqn
\n" ); document.write( "but, $\"angleA=4%2AangleB\"$ ,= $\"A=4B\"$ , then
\n" ); document.write( " $\"4B%2BB=90\"$ -----------> $\"cross%285%29B%2Fcross%285%29=cross%2890%2918%2Fcross%285%29\"$
\n" ); document.write( " $\"B=18deg\"$
\n" ); document.write( "And, $\"A=4%2A18=72deg\"$
\n" ); document.write( "In doubt? go back working eqn,
\n" ); document.write( " $\"72%2B18=90\"$
\n" ); document.write( " $\"90=90\"$
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo
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