document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=2598>Question 2598</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve the questions give below by factorization<BR>\n" );
document.write( "  (1)3x2+x=1   (2)4x2+9=12x (3)5x(x+2)=4(3x=1) (4)2x+7=x2   (5)x2-3x=3x=7 (6)3(4x-1)=x2       </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #1119 by </B><A HREF=/tutors/aboutme.mpl?userid=kiru_khandelwal><B>kiru_khandelwal(79)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=kiru_khandelwal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=1119\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4x2 + 9 = 12x<BR>\n" );
document.write( "=> 4x2 - 12x + 9 = 0\r<BR>\n" );
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document.write( "Now the equation is of the form<BR>\n" );
document.write( "ax2 + bx + c = 0\r<BR>\n" );
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document.write( "Multiply a and c.....and factorize the product 'ac' such that the sum of the factors is b\r<BR>\n" );
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document.write( "In our case a=4 b = -12 and c = 9\r<BR>\n" );
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document.write( "a*c = 4*9 = 36\r<BR>\n" );
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document.write( "Now we have to split 36 into factors whose sum is -12<BR>\n" );
document.write( "so 36 = (-6)*(-6)<BR>\n" );
document.write( "and sum of -6 and -6 is -12\r<BR>\n" );
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document.write( "therefore,<BR>\n" );
document.write( "4x2 -12x + 9 =0 can be written as<BR>\n" );
document.write( "4x2 -6x -6x + 9 = 0<BR>\n" );
document.write( "=> 2x(2x-3)-3(2x-3)=0<BR>\n" );
document.write( "=> Taking the common factore (2x-3) out<BR>\n" );
document.write( "=> (2x-3)(2x-3)=0<BR>\n" );
document.write( "According to the zero product factor....<BR>\n" );
document.write( "2x-3 = 0<BR>\n" );
document.write( "=> x = 3/2\r<BR>\n" );
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document.write( "Similarly others can be solved </SPAN>\n" );
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