document.write( "Question 152228: The present age of a father exceeds 3 times the present age of his son by 2 years. Six years ago, the age of the father exceeded 4 times the age of the son by 4 years. Find the present ages of the son and the father. \n" ); document.write( "
Algebra.Com's Answer #111893 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! The present age of a father exceeds 3 times the present age of his son by 2 years. Six years ago, the age of the father exceeded 4 times the age of the son by 4 years. Find the present ages of the son and the father. \n" ); document.write( ". \n" ); document.write( "Let F = present age of father \n" ); document.write( "and S = present age of son \n" ); document.write( ". \n" ); document.write( "Since we have two unknowns we'll need to find two equations. \n" ); document.write( ". \n" ); document.write( "From:\"The present age of a father exceeds 3 times the present age of his son by 2 years. \" we get equation 1: \n" ); document.write( "F = 3S + 2 \n" ); document.write( ". \n" ); document.write( "From:\"Six years ago, the age of the father exceeded 4 times the age of the son by 4 years.\" we get equation 2: \n" ); document.write( "F-6 = 4(S-6) + 4 \n" ); document.write( ". \n" ); document.write( "Using the value of F from equation 1, substitute it into equation 2 and solve for S: \n" ); document.write( "F-6 = 4(S-6) + 4 \n" ); document.write( "(3S + 2)-6 = 4S - 24 + 4 \n" ); document.write( "3S + 2 -6 = 4S - 24 + 4 \n" ); document.write( "3S - 4 = 4S - 20 \n" ); document.write( "-4 = S - 20 \n" ); document.write( "16 years = S (age of son) \n" ); document.write( ". \n" ); document.write( "Use the above, and substitute it into equation 1 and solve for F: \n" ); document.write( "F = 3S + 2 = 3(16) + 2 = 50 years (age of father)\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |