document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=152215>Question 152215</A>: <I><SPAN STYLE=\"word-break: break-all;\"> use cramers rule or to determine that the system is inconsistent or contains dependent equations: \r<BR>\n" );
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document.write( "y=-4x+2<BR>\n" );
document.write( "2x=3y+8 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #111892 by </B><A HREF=/tutors/aboutme.mpl?userid=nabla><B>nabla(475)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nabla><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=111892\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Put the equations in consistent form:\r<BR>\n" );
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document.write( "4x+y=2<BR>\n" );
document.write( "2x-3y=8\r<BR>\n" );
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document.write( "This gives us a 2x2 system with matrix\r<BR>\n" );
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document.write( "4 1  2<BR>\n" );
document.write( "2 -3 8\r<BR>\n" );
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document.write( "So by Cramer's rule,<BR>\n" );
document.write( "x=<BR>\n" );
document.write( "2 1 <BR>\n" );
document.write( "8 -3<BR>\n" );
document.write( "----<BR>\n" );
document.write( "4 1<BR>\n" );
document.write( "2 -3\r<BR>\n" );
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document.write( "and <BR>\n" );
document.write( "y=<BR>\n" );
document.write( "4 2<BR>\n" );
document.write( "2 8<BR>\n" );
document.write( "----<BR>\n" );
document.write( "4 1<BR>\n" );
document.write( "2 -3\r<BR>\n" );
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document.write( "So, x= (-6-8)/(-12-2)=1<BR>\n" );
document.write( "and y= (32-4)/(-14)=-2\r<BR>\n" );
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document.write( "Thus we have a unique solution. </SPAN>\n" );
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