document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=152219>Question 152219</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I really could use some help with this problem.\r<BR>\n" );
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document.write( "(SUM 14)(-0.4i+4)<BR>\n" );
document.write( "i=1\r<BR>\n" );
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document.write( "I would appreciate any help that I can get. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #111885 by </B><A HREF=/tutors/aboutme.mpl?userid=oscargut><B>oscargut(2103)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oscargut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=oscargut><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=111885\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Sum (from i=1 to i=14)of (-0.4i+4)<BR>\n" );
document.write( "there are 2 ways of doing it<BR>\n" );
document.write( "1) writing all terms \r<BR>\n" );
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document.write( "Sum = S = [-0.4(1)+4]+[-0.4(2)+4]+.......[-0.4(14)+4]=14\r<BR>\n" );
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document.write( "2) using that sum(from i=0 to i=n)of (i)=i(i+1)/2\r<BR>\n" );
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document.write( "(Example sum (from i=1 to i=5) of (i) is 5(6)/2=15)\r<BR>\n" );
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document.write( "then the sum S= Sum (from i=1 to i=14)of (-0.4i+4)=(using properties of a finite sum)=-0.4[sum (from i=1 to i=14) of (i)]+14(4)=<BR>\n" );
document.write( "-0.4[14*15/2]+56=-0.4(105)+56=-42+56=14\r<BR>\n" );
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document.write( "Answer: S=14<BR>\n" );
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