document.write( "Question 152220: if the distance of a falling object is directly proportionae to the square of the time it falls before hitting ground . if the object fell 144 ft in 3 seconds how far will ithave fallen by the end of 4 seconds.how dO I put this as an equation?
\n" ); document.write( "I put it together as
\n" ); document.write( "if the equation is 144 X 4^2 / 3^2? what would Ido next?
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Algebra.Com's Answer #111884 by oscargut(2103)\"\" \"About 
You can put this solution on YOUR website!
d=distance
\n" ); document.write( "t=time
\n" ); document.write( "K=constant of proportion
\n" ); document.write( "the distance of a falling object is directly proportionae to the square of the time it falls before hitting ground
\n" ); document.write( "then d=Kt^2
\n" ); document.write( "the object fell 144 ft in 3 seconds
\n" ); document.write( "then 144=K(3)^2
\n" ); document.write( "then 144=9K
\n" ); document.write( "then K=16
\n" ); document.write( "then equation is d=16t^2\r
\n" ); document.write( "\n" ); document.write( "so if t =4 d=16(4)^2=16^2=256
\n" ); document.write( "Answer: it falls 256 ft after 4 seconds
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