document.write( "Question 152173: solve the system using your choice of method:\r
\n" ); document.write( "\n" ); document.write( "3x^2-2y^2=1
\n" ); document.write( "4x-y=3
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Algebra.Com's Answer #111879 by orca(409)\"\" \"About 
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3x^2-2y^2=1...........(1)
\n" ); document.write( "4x-y=3 ...............(2)
\n" ); document.write( "From equation (2) we get
\n" ); document.write( "y = 4x - 3.
\n" ); document.write( "Substituting it into equation, we have
\n" ); document.write( "3x^2 - 2(4x - 3)^2 = 1
\n" ); document.write( "Solving for x, we obtain:
\n" ); document.write( "3x^2 - 2(16x^2 - 24x + 9) = 1
\n" ); document.write( "3x^2 - 32x^2 + 48x - 18 = 1
\n" ); document.write( "-29x^2 + 48x - 19 = 0
\n" ); document.write( "29x^2 - 48x + 19 = 0
\n" ); document.write( "(29x - 19)(x - 1) = 0
\n" ); document.write( "So x = 19/29 or x = 1
\n" ); document.write( "Substituting x = 19/29 into y = 4x - 3, we have
\n" ); document.write( "y = 4(19/29) - 3 = -11/29
\n" ); document.write( "Substituting x = 1 into y = 4x - 3, we have
\n" ); document.write( "y = 4*1 - 3 = 1
\n" ); document.write( "So the solutions to the original simultaneous equations are
\n" ); document.write( "x = 19/29
\n" ); document.write( "y = -11/29
\n" ); document.write( "OR
\n" ); document.write( "x = 1
\n" ); document.write( "y = 1\r
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