document.write( "Question 152168: how much cream and milk to the nearest thousandth of a gallon must be mixed together to obtain 50 gallons of cream that contains 12.5% butterfat\r
\n" ); document.write( "\n" ); document.write( "facts:\r
\n" ); document.write( "\n" ); document.write( "how many gallons of cream containing 25% butterfat and milk containing 3.5% butter fat must be mixed to obtain 50 gall of cream containing 12.5% butterfat?
\n" ); document.write( "

Algebra.Com's Answer #111847 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
how much cream and milk to the nearest thousandth of a gallon must be mixed together to obtain 50 gallons of cream that contains 12.5% butterfat
\n" ); document.write( "facts:
\n" ); document.write( "how many gallons of cream containing 25% butterfat and milk containing 3.5% butter fat must be mixed to obtain 50 gall of cream containing 12.5% butterfat?
\n" ); document.write( ":
\n" ); document.write( "Let x = amt of 25% butterfat stuff
\n" ); document.write( "then
\n" ); document.write( "(50-x) = amt of 3.5% stuff
\n" ); document.write( ";
\n" ); document.write( "Write an equation using decimals for %
\n" ); document.write( ".25x + .035(50-x) = .125(50)
\n" ); document.write( ":
\n" ); document.write( "Multiply what's inside the brackets
\n" ); document.write( ".25x + 1.75 - .035x = 6.25
\n" ); document.write( ":
\n" ); document.write( ".25x - .035x = 6.25 - 1.75
\n" ); document.write( ":
\n" ); document.write( ".215x = 4.5
\n" ); document.write( "x = \"4.5%2F.215\"
\n" ); document.write( "x = 20.930 gal of the 25% stuff
\n" ); document.write( "then
\n" ); document.write( "50 - 20.930 = 29.070 of the 3.5% stuff
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solution on calc:
\n" ); document.write( ".25(20.93) + .035(29.07) = .125(50)
\n" ); document.write( " 5.2325 + 1.017 = 6.25
\n" ); document.write( " 6.2495 ~ 6.25
\n" ); document.write( "
\n" );