document.write( "Question 152168: how much cream and milk to the nearest thousandth of a gallon must be mixed together to obtain 50 gallons of cream that contains 12.5% butterfat\r
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document.write( "how many gallons of cream containing 25% butterfat and milk containing 3.5% butter fat must be mixed to obtain 50 gall of cream containing 12.5% butterfat? \n" );
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Algebra.Com's Answer #111847 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! how much cream and milk to the nearest thousandth of a gallon must be mixed together to obtain 50 gallons of cream that contains 12.5% butterfat \n" ); document.write( "facts: \n" ); document.write( "how many gallons of cream containing 25% butterfat and milk containing 3.5% butter fat must be mixed to obtain 50 gall of cream containing 12.5% butterfat? \n" ); document.write( ": \n" ); document.write( "Let x = amt of 25% butterfat stuff \n" ); document.write( "then \n" ); document.write( "(50-x) = amt of 3.5% stuff \n" ); document.write( "; \n" ); document.write( "Write an equation using decimals for % \n" ); document.write( ".25x + .035(50-x) = .125(50) \n" ); document.write( ": \n" ); document.write( "Multiply what's inside the brackets \n" ); document.write( ".25x + 1.75 - .035x = 6.25 \n" ); document.write( ": \n" ); document.write( ".25x - .035x = 6.25 - 1.75 \n" ); document.write( ": \n" ); document.write( ".215x = 4.5 \n" ); document.write( "x = \n" ); document.write( "x = 20.930 gal of the 25% stuff \n" ); document.write( "then \n" ); document.write( "50 - 20.930 = 29.070 of the 3.5% stuff \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution on calc: \n" ); document.write( ".25(20.93) + .035(29.07) = .125(50) \n" ); document.write( " 5.2325 + 1.017 = 6.25 \n" ); document.write( " 6.2495 ~ 6.25 \n" ); document.write( " |