document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=152170>Question 152170</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a grocer needs to mix raisins at $2.00 per lbs with granola @ $3.25 per lbs to obtain 10 lbs of mixture that cost $2.50 per lb. how many pounds of each must be used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #111841 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=111841\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a grocer needs to mix raisins at $2.00 per lbs with granola @ $3.25 per lbs to obtain 10 lbs of mixture that cost $2.50 per lb. how many pounds of each must be used?<BR>\n" );
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document.write( "Let x = lbs of raisins<BR>\n" );
document.write( "10-x = lbs of granola<BR>\n" );
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document.write( "2x + 3.25(10-x) = 2.50(10)<BR>\n" );
document.write( "2x + 32.5 - 3.25x = 25<BR>\n" );
document.write( "32.5 - 1.25x = 25<BR>\n" );
document.write( "32.5 = 25 + 1.25x<BR>\n" );
document.write( "7.5 = 1.25x<BR>\n" );
document.write( "6 lbs = x (raisins)<BR>\n" );
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document.write( "10-x = 10-6 = 4 lbs (granola)<BR>\n" );
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