document.write( "Question 152185: Could you please help me with this inequality? ( \">=\" is supposed to be greater than or equal to)\r
\n" ); document.write( "\n" ); document.write( "Solve the inequality. \"+x%2F%28x%2B1%29%3E=3x+\"
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Algebra.Com's Answer #111840 by oscargut(2103)\"\" \"About 
You can put this solution on YOUR website!
\"+x%2F%28x%2B1%29%3E=3x+\"
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\n" ); document.write( "\n" ); document.write( "\"+x%2F%28x%2B1%29-3x%3E=0+\"
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\n" ); document.write( "\n" ); document.write( "\"+%28x-3x%28x%2B1%29%29%2F%28x%2B1%29%3E=0+\"\r
\n" ); document.write( "\n" ); document.write( "\"+%28-3x%5E2-2x%29%2F%28x%2B1%29%3E=0+\"
\n" ); document.write( "\"+x%2A%28-3x-2%29%2F%28x%2B1%29%3E=0+\"\r
\n" ); document.write( "\n" ); document.write( "sign of x*(-3x-2)is --------0++++++0-----
\n" ); document.write( ".............................................-2/3...........0
\n" ); document.write( "sign of x+1 is --0+++++++++++++++
\n" ); document.write( "..........................-1\r
\n" ); document.write( "\n" ); document.write( "sign of f(x) +++*-----0++++++0----- (* symbol means does not exists)
\n" ); document.write( ".........................-1..........-2/3........0\r
\n" ); document.write( "\n" ); document.write( "then f is >=0 when x<-1 or -2/3\n" ); document.write( "
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