document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=152136>Question 152136</A>: <I><SPAN STYLE=\"word-break: break-all;\"> factor by grouping:\r<BR>\n" );
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document.write( "2x^2+12x+3x+18\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #111824 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=111824\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For:<BR>\n" );
document.write( "2x^2+12x+3x+18<BR>\n" );
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document.write( "Notice that of there is NO common factor for the four terms.  The idea is to group  terms together so there is a common factor.<BR>\n" );
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document.write( "Grouping:<BR>\n" );
document.write( "(2x^2+12x) + (3x+18)<BR>\n" );
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document.write( "Now, factor each \"sub group\":<BR>\n" );
document.write( "2x(x+6) + 3(x+6)<BR>\n" );
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document.write( "Between the two terms above, the common factor is (x+6), factor it out:<BR>\n" );
document.write( "(x+6)(2x+3)\r<BR>\n" );
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