document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=152141>Question 152141</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man is 41 years old and his son is 9. In how many years will the father be three times as old as the son? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #111822 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=111822\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "Let x = number of years until father will be 3 times as old as son<BR>\n" );
document.write( ".<BR>\n" );
document.write( "From the statement of the problem, we get our equation:<BR>\n" );
document.write( "41+x = 3(9+x)<BR>\n" );
document.write( "41 + x = 27 + 3x<BR>\n" );
document.write( "41 = 27 + 2x<BR>\n" );
document.write( "14 = 2x<BR>\n" );
document.write( "7 = x<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Therefore, in 7 years the man will be three times as old as the son. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );